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- double precision function ddotf(n,dx,incx,dy,incy)
- c
- c forms the dot product of two vectors.
- c uses unrolled loops for increments equal to one.
- c jack dongarra, linpack, 3/11/78.
- c modified 12/3/93, array(1) declarations changed to array(*)
- c
- double precision dx(*),dy(*),dtemp
- integer i,incx,incy,ix,iy,m,mp1,n
- c
- ddotf = 0.0d0
- dtemp = 0.0d0
- if(n.le.0)return
- if(incx.eq.1.and.incy.eq.1)go to 20
- c
- c code for unequal increments or equal increments
- c not equal to 1
- c
- ix = 1
- iy = 1
- if(incx.lt.0)ix = (-n+1)*incx + 1
- if(incy.lt.0)iy = (-n+1)*incy + 1
- do 10 i = 1,n
- dtemp = dtemp + dx(ix)*dy(iy)
- ix = ix + incx
- iy = iy + incy
- 10 continue
- ddotf = dtemp
- return
- c
- c code for both increments equal to 1
- c
- c
- c clean-up loop
- c
- 20 m = mod(n,5)
- if( m .eq. 0 ) go to 40
- do 30 i = 1,m
- dtemp = dtemp + dx(i)*dy(i)
- 30 continue
- if( n .lt. 5 ) go to 60
- 40 mp1 = m + 1
- do 50 i = mp1,n,5
- dtemp = dtemp + dx(i)*dy(i) + dx(i + 1)*dy(i + 1) +
- * dx(i + 2)*dy(i + 2) + dx(i + 3)*dy(i + 3) + dx(i + 4)*dy(i + 4)
- 50 continue
- 60 ddotf = dtemp
- return
- end
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